Practice question
Question
A lead storage battery delivers 1 A for 4825 s. What is the mass of PbSO₄ (molar mass 303 g/mol) formed at the cathode? (F = 96500 C/mol)
Explanation
Charge = 1 × 4825 = 4825 C . Cathode: PbO₂ + SO₄²⁻ + 4H⁺ + 2e⁻ → PbSO₄ + 2H₂O , 1 mol PbSO₄ requires 2F. Faradays = (4825/96500) = 0.05 F , Moles = (0.05/2) = 0.025 mol , Mass = 0.025 × 303 = 7.575 g .
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