Practice question
Question
A copper rod of length 80cm at 40∘C is cooled until its length decreases by 0.0136cm. What is the final temperature? (αl\=1.7×10−5K−1)
Explanation
Given: L0 = 80cm, ΔL = −0.0136cm, αl = 1.7×10−5K−1, T1 = 40∘C. ΔL = L0αlΔT⇒−0.0136 = 80×1.7×10−5×ΔT. ΔT = −0.013680×1.7×10−5 = −0.01361.36×10−3 = −10K. T2 = 40−10 = 30∘C.
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