Practice question
Question
A cell reaction has Δr G° = -212300 J/mol and involves 2 electrons at 298 K. What is the equilibrium constant?
Explanation
Δr G° = -n F E°cell , E°cell = (212300/2 × 96500) = 1.10 V . E°cell = (0.059/n) log Kc , 1.10 = (0.059/2) log Kc , log Kc = 37.29, Kc ≈ 10³⁷ .
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