Calculate the kinetic energy of an electron ejected from a metal with nu_0 = 5.0 × __10POWâ‚â‚„__Hz by light of nu = 7
Given: Calculate the kinetic energy of an electron ejected from a metal with nu_0 = 5.0 × __10POWâ‚â‚„__Hz by light of nu = 7.0 × __10POWâ‚â‚„__Hz. (h = 6.626 × 10â»Â³â´ J s) These values define the system as per NCERT data. Formula: Kinetic energy = h(nu - nu_0) = 6.626 × 10â»Â³â´ × (7.0 × __10POWâ‚â‚„__- 5.0 × __10POWâ‚â‚„__) = 6.626 × 10â»Â³â´ × 2.0 × __10POWâ‚â‚„__= 1.325 × 10â»Â¹â¹ J.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.