Practice question

Given: Calculate the kinetic energy of an electron ejected from a metal with nu_0 = 5.0 × __10POW₁₄__Hz by light of nu = 7.0 × __10POW₁₄__Hz. (h = 6.626 × 10⁻³⁴ J s) These values define the system as per NCERT data. Formula: Kinetic energy = h(nu - nu_0) = 6.626 × 10⁻³⁴ × (7.0 × __10POW₁₄__- 5.0 × __10POW₁₄__) = 6.626 × 10⁻³⁴ × 2.0 × __10POW₁₄__= 1.325 × 10⁻¹⁹ J.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.