#Collisions

PHYSICS

A 3 kg mass moving at 12 m/s collides elastically with an identical stationary mass. What is the speed of the first mass

Given: A 3 kg mass moving at 12 m/s collides elastically with an identical stationary mass. What is the speed of the first mass after collision? These values define the system as per NCERT data. Formula: For equal masses in elastic collision, v_{1f = 0 m/s (first mass stops).. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

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PHYSICS

A 6 kg mass at 4 m/s collides inelastically with a stationary 2 kg mass. What is the final speed?

Given: A 6 kg mass at 4 m/s collides inelastically with a stationary 2 kg mass. What is the final speed? These values define the system as per NCERT data. Formula: Momentum conservation: 6 × 4 = (6 + 2) v_f Rightarrow 24 = 8 v_f Rightarrow v_f = 3 m/s .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

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PHYSICS

A 2 kg ball moving at 6 m/s collides elastically with a stationary 4 kg ball. What is the speed of the 4 kg ball after c

Given: A 2 kg ball moving at 6 m/s collides elastically with a stationary 4 kg ball. What is the speed of the 4 kg ball after collision? These values define the system as per NCERT data. Formula: For elastic collision: v_{2f = 2 m_1/m_1 + m_2 v_{1i = 2 × 2/2 + 4 × 6 = 4/6 × 6 = 4 m/s .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

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PHYSICS

A 0.25 kg ball moving at 18 m/s at 53° to a wall rebounds at the same speed and angle. What is the impulse perpendicular

Given: A 0.25 kg ball moving at 18 m/s at 53° to a wall rebounds at the same speed and angle. What is the impulse perpendicular to the wall? (Take sin 53° = 0.8, cos 53° = 0.6 ) These values define the system as per NCERT data. Formula: Initial: p_{x1 = m v cos 53° = 0.25 × 18 × 0.6 = 2.7 kg m/s. This is standard NCERT relation. Substitution & Calculation: Perpendicular component (x-axis) reverses upon rebound. . Final: p_{x2 = -m v cos 53° = -0.25 × 18 × 0.6 = -2.7 kg m/s . Impulse: Δ p_x = -2.7 - 2.7 = -5.4 N s . Magnitude: |Δ p_x| = 5.4 N s . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Relevant Physics topic covering fundamental principles,

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PHYSICS

A 10 kg mass at 8 m/s collides inelastically with a stationary 5 kg mass. What is the final speed?

Given: A 10 kg mass at 8 m/s collides inelastically with a stationary 5 kg mass. What is the final speed? These values define the system as per NCERT data. Formula: Momentum conservation: 10 × 8 = (10 + 5) v_f Rightarrow 80 = 15 v_f Rightarrow v_f = 80/15 approx 5.33 m/s .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

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PHYSICS

A 2.5 kg ball at 16 m/s collides elastically with a stationary 7.5 kg ball. What is the speed of the 7.5 kg ball after c

Given: A 2.5 kg ball at 16 m/s collides elastically with a stationary 7.5 kg ball. What is the speed of the 7.5 kg ball after collision? These values define the system as per NCERT data. Formula: For elastic collision: v_{2f = 2 m_1/m_1 + m_2 v_{1i = 2 × 2.5/2.5 + 7.5 × 16 = 5/10 × 16 = 8 m/s .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

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