Practice question
Question
A plane sheet has \( \sigma = 2.66 \times 10^{-11} \, \text{C/m}^2 \). What is the electric field near
it?
Explanation
**Field intensity** at distance r follows inverse-square law E = (1/4π ε₀)·q/r². At midpoint between two charges, fields superpose vectorially; if charges opposite, fields add in same direction, enhancing magnitude to E = E₁ + E₂. E = (sigma/2 ε₀) . E = (2.66 × 10⁻¹¹/2 × 8.854 × 10⁻¹²) = 1.5 N/C . Substituting values gives 1.5 N/C, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency. This aligns with NCERT Class 11 treatment, emphasizing conservation, symmetry and dimensional consistency useful for CBSE, NEET and CUET.
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