Practice question

Given: A 6 kg mass at 4 m/s collides inelastically with a stationary 2 kg mass. What is the final speed? These values define the system as per NCERT data. Formula: Momentum conservation: 6 × 4 = (6 + 2) v_f Rightarrow 24 = 8 v_f Rightarrow v_f = 3 m/s .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.