Practice question
Question
Two cells of emf \( 4 \, \text{V} \) and \( 6 \, \text{V} \) with internal resistances \( 1 \, \Omega
\) and \( 2 \, \Omega \) respectively are connected in series. What is the equivalent emf and internal
resistance of the combination?
Explanation
**Temperature dependence** of resistance R_t = R₀[1+α(T-T₀)], α temperature coefficient (per °C), R₀ resistance at T₀ (Ω). For metals α positive ≈10⁻³ /°C, resistance increases with temperature because τ decreases due to increased phonon scattering, n nearly constant. For series: εₑq = ε₁ + ε₂ = 4 + 6 = 10 V . Internal resistance: rₑq = r₁ + r₂ = 1 + 2 = 3 Ω . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation yields 10 V, 3 Ω,
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