Practice question

**Isobaric process** constant pressure, work W = P ΔV = P(V₂ - V₁) = n R ΔT, for expansion ΔV positive W positive, for compression negative, heat Q = n C_p ΔT, ΔU = n C_v ΔT. Isothermal process constant temperature ΔU=0, work W = n R T ln(V₂/V₁) = n R T ln(P₁/P₂), Q = W, heat absorbed equals work done. W = P Δ V , P V = μ R T . Δ V = 12 - 6 = 6 L .Initial P = (μ R T)/(V₁) , but directly: W = μ R T ((V₂ - V₁)/(V₁)) , adjust via P