Practice question

**Compound microscope** M = m_o × M_e, objective magnification m_o = v_o/u_o ≈ L/f_o, L tube length, eyepiece M_e = 1+D/f_e (image at D) or D/f_e (infinity). Objective forms real inverted magnified image at focal plane of eyepiece, eyepiece acts as simple microscope magnifying it. The eyepiece in a compound microscope acts as a magnifying lens, taking the real, inverted image formed by the objective and producing a larger, virtual image for the observer. It enhances the angular size of the intermediate image, making it appear magnified without altering its orientation. Substituting values gives Magnifies the intermediate image, which matches expected image position and magnification