Skip to content

Question

A system absorbs 710 J of heat and performs 260 J of work. What is the change in internal energy?

Options

Choose one · Correct answer highlighted

Explanation

**Gamma determination** γ = C_p/C_v, C_p - C_v = R, for monatomic f=3 C_v=3/2 R C_p=5/2 R γ=1.67, diatomic f=5 C_v=5/2 R C_p=7/2 R γ=1.4, adiabatic relation P V^γ = const allows γ determination from P-V measurements, slope of log P vs log V = -γ. First Law: Δ Q = Δ U + Δ W . Δ Q = 710 , Δ W = 260 (work by system). 710 = Δ U + 260 ⇒ Δ U = 710 - 260 = 450 J . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W = P ΔV, isothermal

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.