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Question

A stationary wave is given by \( y = 0.08 \sin (\frac{\pi x}{3}) \cos (60\pi t) \), where \( x \) and
\( y \) are in meters and \( t \) in seconds. What is the distance between a node and the next antinode?

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Explanation

**Stationary waves** form when identical progressive waves traveling opposite directions interfere, y = 2A sin(kx) cos(ωt), nodes where sin(kx)=0, antinodes where |sin(kx)|=1. For string fixed at both ends, allowed wavelengths λₙ = 2L/n, frequencies fₙ = n·v/(2L), n = 1,2,3… harmonic number. Form: y = A sin (kx) cos (ω t) , k = (π/3) rad/m . Wavelength: λ = (2π/k) = (2π/(π/3)) = 6 m . Distance between node and antinode: (λ/4) = (6/4) = 1.5 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 1.5 m, illustrating frequency-length-speed interdependence and quantization by boundaries.

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