Skip to content

Question

A stationary wave on a string fixed at both ends has a frequency of 100 Hz and a wave speed of 40 m/s.
What is the length of the string?

Options

Choose one · Correct answer highlighted

Explanation

**Quantization due to boundaries** leads to discrete harmonic series. Frequency difference between harmonics is f₁, so f₃ - f₁ = 2f₁ = v/L. Understanding node-antinode pattern explains resonance and overtones in strings. Fundamental: v₁ = (v/2L) . 100 = (40/2L) ⇒ 2L = (40/100) ⇒ 2L = 0.4 ⇒ L = 0.2 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 0.2 m, illustrating frequency-length-speed interdependence and quantization by boundaries.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.