Practice question
Question
A stationary wave on a string fixed at both ends has a frequency of 100 Hz and a wave speed of 40 m/s.
What is the length of the string?
Explanation
**Quantization due to boundaries** leads to discrete harmonic series. Frequency difference between harmonics is f₁, so f₃ - f₁ = 2f₁ = v/L. Understanding node-antinode pattern explains resonance and overtones in strings. Fundamental: v₁ = (v/2L) . 100 = (40/2L) ⇒ 2L = (40/100) ⇒ 2L = 0.4 ⇒ L = 0.2 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 0.2 m, illustrating frequency-length-speed interdependence and quantization by boundaries.
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