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Question

A dipole with charges \( +6 \, \mu\text{C} \) and \( -6 \, \mu\text{C} \) separated by 2 mm is in a
field \( 8 \times 10^4 \, \text{N/C} \) at 60°. What is the torque?

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Explanation

**Electric dipole** consists of charges +q and -q separated by 2a, dipole moment p = q·2a, vector from negative to positive, unit C·m. In uniform field E, torque τ = p × E, magnitude τ = p E sinθ, tending to align p with E, potential energy U = -p·E = -p E cosθ. Dipole moment: p = q × 2a = 6 × 10⁻⁶ × 2 × 10⁻³ = 1.2 × 10⁻⁸ C m . Torque: tau = p E sin θ = 1.2 × 10⁻⁸ × 8 × 10⁴ × sin 60° = 9.6 × 10⁻⁴ × (√(3)/2) = 8.31 × 10⁻⁴ N

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