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Question

A conducting sphere of radius 21 cm has an electric field of \( 8 \times 10^3 \, \text{N/C} \) at 42 cm
from its center. What is the charge?

Options

Choose one · Correct answer highlighted

Explanation

**Dipole moment** governs torque and energy in external field. Axial field stronger than equatorial, torque maximum at θ = 90°, zero when aligned. Work done rotating dipole relates to ΔU = pE(1 - cosθ), explaining stable equilibrium at θ = 0°. E = (k q/r²) . 8 × 10³ = 9 × 10⁹ × (q/(0.42)²) . q = (8 × 10³ × 0.1764/9 × 10⁹) = 1.57 × 10⁻⁷ C . Substituting values gives 1.57 × 10⁻⁷ C, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency.

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