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#cylindrical rod

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A cylindrical rod of length 0.5 m and radius 0.01 m is compressed by a force of 5000 N. If the compressive stress is 5 ×

Stress: Stress = F / A. Rearrange: A = F / Stress. Substitute: A = 5000 / (5 × 106) = 10-3 m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10-3 m2. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.