Skip to content

Question

What is the path difference for the fourth bright fringe in a double-slit experiment?

Options

Choose one · Correct answer highlighted

Explanation

**Convex lens focusing** plane wave into point because lens introduces phase delay proportional to thickness, converting plane wavefront to spherical converging to focal point, property ensures rays parallel to axis meet at focus, spherical aberration minimized for paraxial rays, lensmaker's formula determines focal length. Constructive interference occurs at Δ = nλ . For the fourth bright fringe, n = 4 , so Δ = 4λ . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ, I = I₀ cos²θ, n = c/v, sinC = 1/n, λ' = λ/n and A = 2a cos(φ/2), calculation gives 4λ, illustrating interference, diffraction and polarization principles.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.