Practice question
Question
What is the change in internal energy when 1 mole of an ideal gas is heated from 300 K to 350 K at constant volume? ( C_v = 20.8 J mol⁻¹ K⁻¹ )
Explanation
**Quasi-static process** infinitely slow, system always near equilibrium, reversible, can be represented as continuous path on P-V diagram, non-quasi-static rapid process non-equilibrium, work W = ∫ P_ext dV, for quasi-static P_ext = P_system, work = ∫ P dV, zeroth law ensures temperature defined throughout quasi-static. Δ U = μ C_v Δ T . μ = 1 , C_v = 20.8 , Δ T = 350 - 300 = 50 . Δ U = 1 × 20.8 × 50 = 1040 J . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W = P ΔV, isothermal W = n R
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