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Question

Two waves \( y_1 = 4 \sin (6x - 18t) \) and \( y_2 = 4 \sin (6x - 18t + \frac{\pi}{3}) \) interfere.
What is the amplitude of the resultant wave?

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Explanation

**Wave addition** governed by phase difference determines resultant intensity ∝ A². Phase arises from path difference Δ = (2π/λ)·Δx, and resultant formula captures interference condition quantitatively for NCERT problems. Amplitude: A = 2a cos (Φ/2) , a = 4 m , Φ = (π/3) . A = 2 × 4 cos (π/6) = 8 × (√(3)/2) ≈ 6.93 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 6.9 m, illustrating frequency-length-speed interdependence and quantization by boundaries.

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