Practice question
Question
Two charges 7 μC and -2 μC are at (8, 0, 0) and (-8, 0, 0) cm . What is the potential at midpoint? (Take 1/4 π ε_0 = 9 × 10⁹Nm² C^{-2 ).
Explanation
Given:
Two charges 7 μC and -2 μC are at (8, 0, 0) and (-8, 0, 0) cm . What is the potential at midpoint? (Take 1/4 π ε_0 = 9 × 10⁹Nm² C^{-2 ).
Formula:
Distance to midpoint = 0.08 m.
Substitution & Calculation:
V = 9 × 10⁹( frac7 × 10⁻⁶⁰.08 + frac-2 × 10⁻⁶⁰.08 ) = 9 × 10⁹ × frac5 × 10⁻⁶⁰.08 = 5.625 × 10⁵V .
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
Discussion
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