Skip to content

Question

Two cells in parallel have emf \( 6 \, \text{V} \) and \( 3 \, \text{V} \) with internal resistances \(
3 \, \Omega \) and \( 1 \, \Omega \). What is the equivalent emf?

Options

Choose one · Correct answer highlighted

Explanation

**Ohm's law deviation** at high fields occurs when τ or n vary with E, resistivity ρ = m/(n e² τ) changes, non-ohmic behaviour seen in semiconductors, electrolytes. At moderate fields, linear V-I holds, slope = R. For parallel: εₑq = (ε₁ r₂ + ε₂ r₁/r₁ + r₂) . Substitute: εₑq = (6 × 1 + 3 × 3/3 + 1) = (6 + 9/4) = 3.75 V . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation yields 3.75 V,

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.