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Question

Three charges \( +8 \, \mu\text{C}, -4 \, \mu\text{C}, +2 \, \mu\text{C} \) are at the vertices of an
equilateral triangle of side 1.8 m. What is the force magnitude on \( +8 \, \mu\text{C} \)?

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Explanation

**Vector addition of forces** underlies multi-charge analysis. Each pair contributes independent Coulomb force, resultant obtained by resolving components along axes. Equilibrium occurs when vector sum vanishes, often at symmetric points where contributions balance. F₁ = 9 × 10⁹ × (8 × 4 × 10⁻¹²/(1.8)²) = 0.0889 N (attractive). F₂ = 9 × 10⁹ × (8 × 2 × 10⁻¹²/(1.8)²) = 0.0444 N (repulsive). Angle 60°. Net F = √(F₁² + F₂² + 2 F₁ F₂ cos 60°) = √(0.0889² + 0.0444² + 0.00395) = 0.108 N . Substituting values gives 0.108 N, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency.

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