Practice question
Question
Light of wavelength 450 nm is incident on a metal with work function 1.9 eV . What is the maximum kinetic energy in eV? (Take h c = 1240 eV nm )
Explanation
Given:
Light of wavelength 450 nm is incident on a metal with work function 1.9 eV . What is the maximum kinetic energy in eV? (Take h c = 1240 eV nm )
Formula:
E = h c/lambda = 1240/450 approx 2.756 eV.
Substitution & Calculation:
K_{max = E - phi_0 = 2.756 - 1.9 approx 0.856 eV .
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
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