Practice question
Question
In an isobaric process, 1 mole of an ideal gas expands from 8 L to 16 L at 360 K . What is the work done by the gas? ( R = 8.3 J mol⁻¹ K⁻¹ )
Explanation
**Second law Kelvin-Planck statement** no process possible whose sole result is absorption of heat from reservoir and complete conversion to work, heat engine must have at least two reservoirs hot and cold, efficiency η = W/Q_h =1 - Q_c/Q_h <1, impossible 100% efficient, Carnot efficiency η_Carnot =1 - T_c/T_h maximum possible between T_h and T_c. W = P Δ V , P V = μ R T . Δ V = 16 - 8 = 8 L . P = (μ R T)/(V₁) = (1 × 8.3 × 360)/(8) = 373.5 atm (unit correction needed).Directly: W = μ R T ((V₂ - V₁)/(V₁)) , but
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