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Question

In a circuit with two identical cells connected in series, if one cell’s polarity is reversed, what
happens to the total emf?

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Choose one · Correct answer highlighted

Explanation

**Temperature dependence** of resistance R_t = R₀[1+α(T-T₀)], α temperature coefficient (per °C), R₀ resistance at T₀ (Ω). For metals α positive ≈10⁻³ /°C, resistance increases with temperature because τ decreases due to increased phonon scattering, n nearly constant. For two identical cells with emf ε , in series, total emf = ε + ε = 2ε . If one is reversed, it becomes ε - ε = 0 , as the emfs cancel out. Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation yields

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