Practice question
Question
An object is placed \( 15 \, \text{cm} \) in front of a concave mirror of focal length \( 10 \,
\text{cm} \). Where is the image formed?
Explanation
**Mirror formula** 1/f = 1/v + 1/u governs spherical mirrors, f = R/2, R radius of curvature (m), u object distance (m), v image distance (m), sign convention: distances in front of mirror negative for real is convention but magnitude used, magnification m = -v/u, concave forms real inverted when object beyond F, virtual erect within F. f = -10 cm , u = -15 cm . (1/v) + (1/-15) = (1/-10) ⇒ (1/v) = (1/-10) + (1/15) = (-3 + 2/30) = (-1/30) . v = -30 cm (real image). Substituting values gives 30 cm, which matches expected image position and magnification from mirror/lens
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