Practice question
Question
A stationary wave on a string fixed at both ends has a frequency of 150 Hz and a wave speed of 45 m/s.
What is the wavelength?
Explanation
**Doppler effect** describes apparent frequency shift due to relative motion between source and observer, f' = f·v/(v ∓ v_s) for source motion, f' = f·(v ± v_o)/v for observer motion, upper signs for approach increasing observed frequency. Motion towards observer compresses wavelength raising f'. Wavelength: λ = (v/v) = (45/150) = 0.3 m . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 0.3 m, illustrating frequency-length-speed interdependence and quantization by boundaries.
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