Practice question
Question
A square loop of side 26 cm rotates at 12 rad/s in a 0.3 T field. What is the maximum emf induced?
Explanation
Given:
A square loop of side 26 cm rotates at 12 rad/s in a 0.3 T field. What is the maximum emf induced?
Formula:
A = (0.26)² = 0.0676 m².
Substitution & Calculation:
ε_0 = N B A omega = 1 × 0.3 × 0.0676 × 12 = 0.24336 V approx 0.243 V .
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
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