Practice question
Question
A square loop of side 26 cm rotates at 12 rad/s in a 0.3 T field. What is the maximum emf induced?
Explanation
**Maximum emf** e₀ = N B A ω, for 180 turns A=0.02 m² B=0.03 T ω=60 rad/s, e₀=180×0.03×0.02×60=6.48 V, illustrating dependence on N, B, A, ω, used in generator design, increasing N or B or A or ω raises output. A = (0.26)² = 0.0676 m² . ε₀ = N B A ω = 1 × 0.3 × 0.0676 × 12 = 0.24336 V ≈ 0.243 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M = e/(dI/dt) and U = ½ L I²,
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