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Question

A spring-mass system has \( m = 0.25 \, \text{kg} \) and \( k = 100 \, \text{N/m} \). What is its
period of oscillation?

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Choose one · Correct answer highlighted

Explanation

**Real oscillators** experience damping, amplitude decreasing with time. Critical damping returns to equilibrium fastest without oscillation, overdamping slows return, underdamping shows decaying oscillations, classification based on b relative to 2mω₀, important for practical systems. Period: T = 2π √((m/k)) = 2π √((0.25/100)) = 2π √(0.0025) = 2π × 0.05 ≈ 0.314 s . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 0.314 s follows, reflecting SHM dependence on amplitude A, ω and system parameters.

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