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Question

A solenoid of 1000 turns/m and area 0.01 m² has \( \mu_r = 2 \). What is its self-inductance? (\( \mu_0
= 4\pi \times 10^{-7} \, \text{H/m} \))

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Explanation

**Energy in inductor** cannot change instantaneously because that would require infinite power, current through inductor continuous, voltage may jump, principle used in chokes, inductive kick, back emf, explaining why inductor opposes change in current. L = μ_r μ₀ n² A l , assume l = 1 m . L = 2 × 4π × 10⁻⁷ × (1000)² × 0.01 × 1 = 0.02513 H ≈ 0.025 H . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M = e/(dI/dt) and U = ½ L I²,

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