Practice question

Given: A rectangular loop of sides 12 cm and 4 cm moves out of a 0.35 T field at 2 m/s perpendicular to the longer side. What is the motional emf? These values define the system as per NCERT data. Formula: varepsilon = B l v, l = 0.04 m. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: varepsilon = 0.35 × 0.04 × 2 = 0.028 V . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.