Practice question

**Conservation of mechanical energy** in undamped SHM implies total energy proportional to amplitude squared A² and spring constant k. E = ½ k A² allows amplitude determination from known E and k via A = √(2E/k), with k = m ω² linking dynamical and energetic descriptions for spring-mass system. Total energy: E = (1/2) m ω² A² = 0.5 × 2 × 5² × 3² = 225 J . Potential energy: U = (1/2) m ω² x² = 0.5 × 2 × 25 × (1.5)² = 56.25 J . Kinetic energy: K = E - U = 225 - 56.25 = 168.75 J . Applying