Practice question

**Spherical conductor capacitance** C = 4π ε₀ R, R radius (m), potential V = Q/C = Q/(4π ε₀ R)=k Q/R. For R=2 cm=0.02 m, Q=2×10⁻⁸ C, V=9×10⁹×2×10⁻⁸/0.02=9000 V, showing high voltage for small sphere with modest charge. Potential difference: V = E₀ ( (4d/5) ) + (E₀/K) ( (d/5) ) = E₀ d ( (4/5) + (1/5 × 6) ) . V = E₀ d ( (4/5) + (1/30) ) = E₀ d × (25/30) = E₀ d × (5/6) . C = (Q/V) = (Q/(5/6) V₀) = (6/5) × 150 = 180 pF . Using V = kQ/r, U = k q₁q₂/r, E =