Practice question
Question
A monatomic ideal gas undergoes an adiabatic expansion, reducing its temperature from 400 K to 300 K . How much work is done by the gas if mu = 1 mole and R = 8.3 J mol⁻¹ K⁻¹ ? ( gamma = 1.67 )
Explanation
**Work and heat** both energy transfer modes, work organized, e.g., lifting weight, compressing gas, electrical current, heat random due to temperature difference, work can be completely converted to heat via friction, but heat cannot be completely converted to work (second law), energy transfer modes include work (mechanical, electrical) and heat (conduction, convection, radiation). Work done: W = (μ R (T₁ - T₂))/(γ - 1) . μ = 1 , R = 8.3 , T₁ = 400 , T₂ = 300 , γ = 1.67 . W = (1 × 8.3 × (400 - 300))/(1.67 - 1) = (8.3 × 100)/(0.67) ≈ 1238.8 J . Using
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.