Skip to content

Question

A mass oscillates with \( v = -6 \sin (4t) \) (in m/s). What is its amplitude?

Options

Choose one · Correct answer highlighted

Explanation

**Distinction between periodic and oscillatory** clarifies all SHM is periodic but not all periodic is SHM. SHM requires linear restoring force and inertia, a ∝ -x, with ω = √(k/m). Functions like sin²ωt have period π/ω but lack a = -ω² x, thus periodic not SHM, while uniform circular motion is periodic without linear oscillation. Velocity: v = -ω A sin (ω t) . Given ω = 4 s⁻¹, vₘₐₓ = ω A = 6 . A = (6/4) = 1.5 m . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A²,

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.