Skip to content

Question

A gas mixture contains 2 g of hydrogen and 32 g of oxygen. What is the ratio of their partial pressures?

Options

Choose one · Correct answer highlighted

Explanation

**Specific heat relation** C_p - C_v = R for ideal gas per mole, Mayer's relation, due to work done at constant pressure, degrees of freedom include translational, rotational, vibrational, each quadratic term contributes ½ R to C_v. P = (μ RT)/(V), P_H₂P_O₂ = μ_H₂μ_O₂.μ_H₂ = (2)/(2) = 1 mol, μ_O₂ = (32)/(32) = 1 mol.Ratio = (1)/(1) = 1:1. Substituting values gives 1:1, which matches expected kinetic theory result, confirming mean free path λ = 1/(√2 n π d²), ideal gas law P V = n R T and v_rms = √(3 R T/M) relations.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.