Practice question

**Molar specific heat** from equipartition C_v = f/2 R, C_p = f/2 R + R, γ = C_p/C_v =1+2/f, for f=3 γ=1.67, f=5 γ=1.4, f=6 γ=1.33, explaining specific heat variation with molecular structure, degrees of freedom determine heat capacity. P = (μ RT)/(V), P_HeP_O₂ = μ_Heμ_O₂.μ_He = (4)/(4) = 1 mol, μ_O₂ = (16)/(32) = 0.5 mol.Ratio = (1)/(0.5) = 2:1. Substituting values gives 2:1, which matches expected kinetic theory result, confirming mean free path λ = 1/(√2 n π d²), ideal gas law P V = n R T and v_rms = √(3 R T/M) relations.