Practice question
Question
A conductor has a resistivity of \( 1.0 \times 10^{-7} \, \Omega \text{m} \) and \( \alpha = 4 \times
10^{-3} \, ^\circ\text{C}^{-1} \) at \( 25^\circ \text{C} \). What is its resistivity at \( 85^\circ
\text{C} \)?
Explanation
**Mobility** μ = v_d/E = e τ/m, τ relaxation time (s), measures ease of electron drift under field E (V/m). Conductivity σ = n e μ = 1/ρ, linking microscopic τ to macroscopic resistivity, explaining why metals conduct well due to large n and τ. Use: rho_t = rho₀ [1 + α (T - T₀)] . Substitute: rho_t = 1.0 × 10⁻⁷ [1 + 4 × 10⁻³ (85 - 25)] . Calculate: rho_t = 1.0 × 10⁻⁷ [1 + 0.24] = 1.0 × 10⁻⁷ × 1.24 = 1.24 × 10⁻⁷ Ω m . Applying I = n e A v_d, R = ρ l/A, R_t
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