Practice question

Given: A 4 Ω resistor dissipates 16 W of power. What is the voltage across it? These values define the system as per NCERT data. Formula: Power: P = V²/R. This is standard NCERT relation. Substitution & Calculation: Rearrange: V = sqrtP R . Substitute: V = sqrt16 × 4 = sqrt64 = 8 V . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.