Practice question

Given: A nucleus has a mass defect of 0.136 u . What is its binding energy in MeV? (Given 1 u = 931.5 MeV/c² ) These values define the system as per NCERT data. Formula: Binding energy = Δ M · c². This is standard NCERT relation. Substitution & Calculation: Δ M = 0.136 u . Energy = 0.136 × 931.5 approx 126.7 MeV . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.