Practice question
Question
A \( 27 \, \text{V} \) battery with negligible internal resistance is connected to a cubical network of
12 resistors, each \( 3 \, \Omega \). What is the total current?
Explanation
**Resistance** R = ρ l/A, ρ resistivity (Ω·m), l length (m), A area (m²), ρ = m/(n e² τ) from Drude model, τ average collision time. Ohm's law V = I R holds when ρ constant, independent of V. Volume constant stretching l→2l implies A→A/2, so R' = ρ·2l/(A/2)=4R, resistance quadruples when length doubles at constant volume. Equivalent resistance: Rₑq = (5/6) R = (5/6) × 3 = (15/6) = 2.5 Ω . Total current: I = (V/Rₑq) = (27/2.5) = 10.8 A . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V =
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