Practice question

**Dielectric polarization** when slab inserted, bound charges appear reducing effective field, capacitance increases by factor K, potential difference for constant charge V = Q/C decreases, for constant voltage charge increases. Dielectric constant K = ε/ε₀ >1, e.g., K≈5 for glass. Electrostatic Potential and Capacitance typically assumes no charge inside a spherical shell, leading to E = 0 . However, if misinterpreted as a charged dielectric sphere (common in advanced contexts but not in the PDF), the field varies as E ∝ r . Since the PDF context implies an empty shell or uniform shell charge, E = 0 . Assuming a misinterpretation, the correct context