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Practice question

MCQ

Question

Why does a conductor’s current density increase when its length is halved while keeping the potential difference constant?

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Explanation

Resistance R = rho l / A . Halving length ( l' = l/2 ) halves R ( R' = R/2 ). Current I = V / R, so I' = V / (R/2) = 2I . Current density j = I / A, so j' = 2I / A = 2j .

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