Practice question
Question
What is the path difference for the fifth dark fringe in a double-slit experiment?
Explanation
**Wave model predicts** light bends away from normal when entering rarer medium because speed increases, Snell's law n₁ sinθ₁ = n₂ sinθ₂, n₁>n₂ so sinθ₂>sinθ₁ θ₂>θ₁ away from normal, towards normal when denser, wavefront slows in denser, Huygens construction shows bending. Destructive interference occurs at Δ = (n + (1/2))λ . For the fifth dark fringe, n = 4 , Δ = (4 + (1/2))λ = (9λ/2) . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ, I = I₀ cos²θ, n = c/v, sinC = 1/n, λ' = λ/n and A = 2a cos(φ/2), calculation gives (9λ/2), illustrating interference, diffraction and polarization principles.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.