Practice question

Given: Two particles of masses 8 kg and 2 kg are at (0, 5) and (10, 0) respectively. What is the distance of their nter of mass from the origin? These values define the system as per NCERT data. Formula: X = (8 × 0) + (2 × 10)/8 + 2 = 20/10 = 2. This is standard NCERT relation. Substitution & Calculation: Y = (8 × 5) + (2 × 0)/8 + 2 = 40/10 = 4 . Distance = sqrt(2)² + (4)² = sqrt4 + 16 = sqrt20 approx 4.47 m . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.