Practice question
Question
The magnetic field contribution \( B_m \) due to a material with \( M = 3.5 \times 10^5 \, \text{A
m}^{-1} \) is: (Take \( \mu_0 = 4\pi \times 10^{-7} \, \text{T m A}^{-1} \)).
Explanation
**Torque on magnetic dipole** in uniform field B is τ = m × B, magnitude τ = m B sinθ, m moment (A·m²), B field (T), θ angle between m and B (degrees). Torque tends to align moment with field, zero at θ = 0°, maximum mB at 90°, direction given by right-hand rule. B_m = μ₀ M . Given: M = 3.5 × 10⁵ A m⁻¹ , μ₀ = 4π × 10⁻⁷ . B_m = 4π × 10⁻⁷ × 3.5 × 10⁵ = 0.4396 T ≈ 0.44 T . Substituting values gives 0.44 T, which matches expected magnitude for this magnetic configuration, confirming dipole
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