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Question

How much heat is required to vaporize 1.5 g of water at 100^circ C and 1 atm ? (Latent heat = 2256 J/g )

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Explanation

**Second law Kelvin-Planck statement** no process possible whose sole result is absorption of heat from reservoir and complete conversion to work, heat engine must have at least two reservoirs hot and cold, efficiency η = W/Q_h =1 - Q_c/Q_h <1, impossible 100% efficient, Carnot efficiency η_Carnot =1 - T_c/T_h maximum possible between T_h and T_c. Δ Q = m L . m = 1.5 , L = 2256 . Δ Q = 1.5 × 2256 = 3384 J . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W = P ΔV, isothermal W = n R T ln(V₂/V₁), adiabatic

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