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Question

At what temperature is the rms speed of helium molecules 1500 m/s? (Atomic mass of He = 4 u, k_B = 1.38 × 10⁻²³ J K⁻¹)

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Explanation

**Gas laws** Boyle, Charles, Gay-Lussac are special cases of ideal gas equation, for constant pressure volume-temperature relation V ∝ T, for constant temperature pressure-volume inverse, for constant volume pressure-temperature direct, enabling calculation of new volume from temperature ratio. v_rms = √((3k_B T)/(m)), m = 4 × 10⁻³⁶.02 × 10²³ = 6.64 × 10⁻²⁷ kg.1500² = 3 × 1.38 × 10⁻²/³ × T6.64 × 10⁻²⁷, T = 2.25 × 10⁶ × 6.64 × 10⁻²⁷/⁴.14 × 10⁻²/³ ≈ 361 K. Substituting values gives 361 K, which matches expected kinetic theory result, confirming mean free path λ = 1/(√2 n π d²), ideal gas law P V =

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